Soli Deo Gloria
Jawaban: 1.lim/(x→∞)=((x-2) (3x+1)^2)/((x+1)(x^2+5))=(f(x))/(g(x))=((x-2)(9x^2+6x+1))/((x+1)(x^2+5))(f(x))/(g(x))=(9x^3+6x^2+1x-18x^2-12x-2)/(x^3+5x+1x^2+5)F(x)=(9x^3-12x^2-11x-2)/(x^3+5x+1x^2+5)=9/1=9Jadi (f(x))/(g(x))=(9x^3)/x^3 =(telah memenuhi sifat yg pertama)2.lim/(x→∞) (akar 4x^2-2x+3)/(2x+5)=(akar 4x^2-2x+3)/(x/((2x+5)/x))lim/(x→∞)=(4x^2-2x+3)/((akar x^2)/(2x+ 5/x))=(akar 4x^2-2x+3)/(x^2/(2+5/x))=(akar 4-(2+3/x)/x)/(2x 5/x)=(2-(2+3/x)/(x ))/(2+5/x)=(2-0+0)/(2+0)=2/2=1Jadi (f(x))/(g(x))=2/2 (telah memenuhi sifat pertama)
Jawaban:
BalasHapus1.lim/(x→∞)=((x-2) (3x+1)^2)/((x+1)(x^2+5))=(f(x))/(g(x))=((x-2)(9x^2+6x+1))/((x+1)(x^2+5))
(f(x))/(g(x))=(9x^3+6x^2+1x-18x^2-12x-2)/(x^3+5x+1x^2+5)
F(x)=(9x^3-12x^2-11x-2)/(x^3+5x+1x^2+5)=9/1=9
Jadi (f(x))/(g(x))=(9x^3)/x^3 =(telah memenuhi sifat yg pertama)
2.lim/(x→∞) (akar 4x^2-2x+3)/(2x+5)=(akar 4x^2-2x+3)/(x/((2x+5)/x))
lim/(x→∞)=(4x^2-2x+3)/((akar x^2)/(2x+ 5/x))
=(akar 4x^2-2x+3)/(x^2/(2+5/x))=(akar 4-(2+3/x)/x)/(2x 5/x)
=(2-(2+3/x)/(x ))/(2+5/x)
=(2-0+0)/(2+0)=2/2=1
Jadi (f(x))/(g(x))=2/2 (telah memenuhi sifat pertama)
Jawaban:
BalasHapus1.lim/(x→∞)=((x-2) (3x+1)^2)/((x+1)(x^2+5))=(f(x))/(g(x))=((x-2)(9x^2+6x+1))/((x+1)(x^2+5))
(f(x))/(g(x))=(9x^3+6x^2+1x-18x^2-12x-2)/(x^3+5x+1x^2+5)
F(x)=(9x^3-12x^2-11x-2)/(x^3+5x+1x^2+5)=9/1=9
Jadi (f(x))/(g(x))=(9x^3)/x^3 =(telah memenuhi sifat yg pertama)
2.lim/(x→∞) (akar 4x^2-2x+3)/(2x+5)=(akar 4x^2-2x+3)/(x/((2x+5)/x))
lim/(x→∞)=(4x^2-2x+3)/((akar x^2)/(2x+ 5/x))
=(akar 4x^2-2x+3)/(x^2/(2+5/x))=(akar 4-(2+3/x)/x)/(2x 5/x)
=(2-(2+3/x)/(x ))/(2+5/x)
=(2-0+0)/(2+0)=2/2=1
Jadi (f(x))/(g(x))=2/2 (telah memenuhi sifat pertama)
Jawaban:
BalasHapus1.lim/(x→∞)=((x-2) (3x+1)^2)/((x+1)(x^2+5))=(f(x))/(g(x))=((x-2)(9x^2+6x+1))/((x+1)(x^2+5))
(f(x))/(g(x))=(9x^3+6x^2+1x-18x^2-12x-2)/(x^3+5x+1x^2+5)
F(x)=(9x^3-12x^2-11x-2)/(x^3+5x+1x^2+5)=9/1=9
Jadi (f(x))/(g(x))=(9x^3)/x^3 =(telah memenuhi sifat yg pertama)
2.lim/(x→∞) (akar 4x^2-2x+3)/(2x+5)=(akar 4x^2-2x+3)/(x/((2x+5)/x))
lim/(x→∞)=(4x^2-2x+3)/((akar x^2)/(2x+ 5/x))
=(akar 4x^2-2x+3)/(x^2/(2+5/x))=(akar 4-(2+3/x)/x)/(2x 5/x)
=(2-(2+3/x)/(x ))/(2+5/x)
=(2-0+0)/(2+0)=2/2=1
Jadi (f(x))/(g(x))=2/2 (telah memenuhi sifat pertama)
Jawaban:
BalasHapus1.lim/(x→∞)=((x-2) (3x+1)^2)/((x+1)(x^2+5))=(f(x))/(g(x))=((x-2)(9x^2+6x+1))/((x+1)(x^2+5))
(f(x))/(g(x))=(9x^3+6x^2+1x-18x^2-12x-2)/(x^3+5x+1x^2+5)
F(x)=(9x^3-12x^2-11x-2)/(x^3+5x+1x^2+5)=9/1=9
Jadi (f(x))/(g(x))=(9x^3)/x^3 =(telah memenuhi sifat yg pertama)
2.lim/(x→∞) (akar 4x^2-2x+3)/(2x+5)=(akar 4x^2-2x+3)/(x/((2x+5)/x))
lim/(x→∞)=(4x^2-2x+3)/((akar x^2)/(2x+ 5/x))
=(akar 4x^2-2x+3)/(x^2/(2+5/x))=(akar 4-(2+3/x)/x)/(2x 5/x)
=(2-(2+3/x)/(x ))/(2+5/x)
=(2-0+0)/(2+0)=2/2=1
Jadi (f(x))/(g(x))=2/2 (telah memenuhi sifat pertama)
Jawaban:
BalasHapus1.lim/(x→∞)=((x-2) (3x+1)^2)/((x+1)(x^2+5))=(f(x))/(g(x))=((x-2)(9x^2+6x+1))/((x+1)(x^2+5))
(f(x))/(g(x))=(9x^3+6x^2+1x-18x^2-12x-2)/(x^3+5x+1x^2+5)
F(x)=(9x^3-12x^2-11x-2)/(x^3+5x+1x^2+5)=9/1=9
Jadi (f(x))/(g(x))=(9x^3)/x^3 =(telah memenuhi sifat yg pertama)
2.lim/(x→∞) (akar 4x^2-2x+3)/(2x+5)=(akar 4x^2-2x+3)/(x/((2x+5)/x))
lim/(x→∞)=(4x^2-2x+3)/((akar x^2)/(2x+ 5/x))
=(akar 4x^2-2x+3)/(x^2/(2+5/x))=(akar 4-(2+3/x)/x)/(2x 5/x)
=(2-(2+3/x)/(x ))/(2+5/x)
=(2-0+0)/(2+0)=2/2=1
Jadi (f(x))/(g(x))=2/2 (telah memenuhi sifat pertama)
Jawaban:
BalasHapus1.lim/(x→∞)=((x-2) (3x+1)^2)/((x+1)(x^2+5))=(f(x))/(g(x))=((x-2)(9x^2+6x+1))/((x+1)(x^2+5))
(f(x))/(g(x))=(9x^3+6x^2+1x-18x^2-12x-2)/(x^3+5x+1x^2+5)
F(x)=(9x^3-12x^2-11x-2)/(x^3+5x+1x^2+5)=9/1=9
Jadi (f(x))/(g(x))=(9x^3)/x^3 =(telah memenuhi sifat yg pertama)
2.lim/(x→∞) (akar 4x^2-2x+3)/(2x+5)=(akar 4x^2-2x+3)/(x/((2x+5)/x))
lim/(x→∞)=(4x^2-2x+3)/((akar x^2)/(2x+ 5/x))
=(akar 4x^2-2x+3)/(x^2/(2+5/x))=(akar 4-(2+3/x)/x)/(2x 5/x)
=(2-(2+3/x)/(x ))/(2+5/x)
=(2-0+0)/(2+0)=2/2=1
Jadi (f(x))/(g(x))=2/2 (telah memenuhi sifat pertama)
Jawaban:
BalasHapus1.lim/(x→∞)=((x-2) (3x+1)^2)/((x+1)(x^2+5))=(f(x))/(g(x))=((x-2)(9x^2+6x+1))/((x+1)(x^2+5))
(f(x))/(g(x))=(9x^3+6x^2+1x-18x^2-12x-2)/(x^3+5x+1x^2+5)
F(x)=(9x^3-12x^2-11x-2)/(x^3+5x+1x^2+5)=9/1=9
Jadi (f(x))/(g(x))=(9x^3)/x^3 =(telah memenuhi sifat yg pertama)
2.lim/(x→∞) (akar 4x^2-2x+3)/(2x+5)=(akar 4x^2-2x+3)/(x/((2x+5)/x))
lim/(x→∞)=(4x^2-2x+3)/((akar x^2)/(2x+ 5/x))
=(akar 4x^2-2x+3)/(x^2/(2+5/x))=(akar 4-(2+3/x)/x)/(2x 5/x)
=(2-(2+3/x)/(x ))/(2+5/x)
=(2-0+0)/(2+0)=2/2=1
Jadi (f(x))/(g(x))=2/2 (telah memenuhi sifat pertama)
Jawaban:
BalasHapus1.lim/(x→∞)=((x-2) (3x+1)^2)/((x+1)(x^2+5))=(f(x))/(g(x))=((x-2)(9x^2+6x+1))/((x+1)(x^2+5))
(f(x))/(g(x))=(9x^3+6x^2+1x-18x^2-12x-2)/(x^3+5x+1x^2+5)
F(x)=(9x^3-12x^2-11x-2)/(x^3+5x+1x^2+5)=9/1=9
Jadi (f(x))/(g(x))=(9x^3)/x^3 =(telah memenuhi sifat yg pertama)
2.lim/(x→∞) (akar 4x^2-2x+3)/(2x+5)=(akar 4x^2-2x+3)/(x/((2x+5)/x))
lim/(x→∞)=(4x^2-2x+3)/((akar x^2)/(2x+ 5/x))
=(akar 4x^2-2x+3)/(x^2/(2+5/x))=(akar 4-(2+3/x)/x)/(2x 5/x)
=(2-(2+3/x)/(x ))/(2+5/x)
=(2-0+0)/(2+0)=2/2=1
Jadi (f(x))/(g(x))=2/2 (telah memenuhi sifat pertama)
Jawaban:
BalasHapus1.lim/(x→∞)=((x-2) (3x+1)^2)/((x+1)(x^2+5))=(f(x))/(g(x))=((x-2)(9x^2+6x+1))/((x+1)(x^2+5))
(f(x))/(g(x))=(9x^3+6x^2+1x-18x^2-12x-2)/(x^3+5x+1x^2+5)
F(x)=(9x^3-12x^2-11x-2)/(x^3+5x+1x^2+5)=9/1=9
Jadi (f(x))/(g(x))=(9x^3)/x^3 =(telah memenuhi sifat yg pertama)
2.lim/(x→∞) (akar 4x^2-2x+3)/(2x+5)=(akar 4x^2-2x+3)/(x/((2x+5)/x))
lim/(x→∞)=(4x^2-2x+3)/((akar x^2)/(2x+ 5/x))
=(akar 4x^2-2x+3)/(x^2/(2+5/x))=(akar 4-(2+3/x)/x)/(2x 5/x)
=(2-(2+3/x)/(x ))/(2+5/x)
=(2-0+0)/(2+0)=2/2=1
Jadi (f(x))/(g(x))=2/2 (telah memenuhi sifat pertama)