Minggu, 16 Februari 2014

Tugas XI IPA 2



Tentukan hasil dan sisi bagi dari pembagian sukubanyak berikut
1.       P(x) = 2x3 + 3x2 + 15x  - 3 oleh (5x – 3)
2.       P(x) = x3 + 2x2 + 8x – 3 oleh (x2 – x – 6)
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6 komentar:

  1. Unknown17 Februari 2014 pukul 17.53

    JAWABAN
    Peny :
    P(x)=2x3 + 3x2 + 15x – 3 oleh (5x – 3)

    5x-3 => x = 3/5
    P(x) = 2x3 + 3x2 + 15x – 3

    X = 3/5 2 3 15 -3

    1 2 10 +

    2 4 17 7 = S(x)

    H(x) = 2x2 + 4x + 17
    S(x) = 7


    Peny :
    P(x) = x3 + 2x2 + 8x – 3 oleh x2 – x – 6

    Q(x) = x2 – x – 6
    (x + 2)(x – 3)
    Q1 = x+2 => x = -2
    Q2 = x-3 => x = 3

    P(x) = x3 + 2x2 + 8x -3

    Q1 = x = -2 1 2 8 -3

    -2 0 -16 +

    1 0 8 19 = S1

    Q2=x = 3 1 0 8

    3 9 +

    1 3 17 = S2
    Jadi, H(x) = x2 + x
    S(x) = Q1 . S2 + S1 = -19x - 21


    BalasHapus
  2. Unknown17 Februari 2014 pukul 17.56

    JAWABAN
    Peny :
    P(x)=2x3 + 3x2 + 15x – 3 oleh (5x – 3)

    5x-3 => x = 3/5
    P(x) = 2x3 + 3x2 + 15x – 3

    X = 3/5 2 3 15 -3

    1 2 10 +

    2 4 17 7 = S(x)

    H(x) = 2x2 + 4x + 17
    S(x) = 7


    Peny :
    P(x) = x3 + 2x2 + 8x – 3 oleh x2 – x – 6

    Q(x) = x2 – x – 6
    (x + 2)(x – 3)
    Q1 = x+2 => x = -2
    Q2 = x-3 => x = 3

    P(x) = x3 + 2x2 + 8x -3

    Q1 = x = -2 1 2 8 -3

    -2 0 -16 +

    1 0 8 19 = S1

    Q2=x = 3 1 0 8

    3 9 +

    1 3 17 = S2
    Jadi, H(x) = x2 + x
    S(x) = Q1 . S2 + S1 = -19x - 21


    BalasHapus
  3. Unknown17 Februari 2014 pukul 17.59

    JAWABAN
    Peny :
    P(x)=2x3 + 3x2 + 15x – 3 oleh (5x – 3)

    5x-3 => x = 3/5
    P(x) = 2x3 + 3x2 + 15x – 3

    X = 3/5 2 3 15 -3

    1 2 10 +

    2 4 17 7 = S(x)

    H(x) = 2x2 + 4x + 17
    S(x) = 7


    Peny :
    P(x) = x3 + 2x2 + 8x – 3 oleh x2 – x – 6

    Q(x) = x2 – x – 6
    (x + 2)(x – 3)
    Q1 = x+2 => x = -2
    Q2 = x-3 => x = 3

    P(x) = x3 + 2x2 + 8x -3

    Q1 = x = -2 1 2 8 -3

    -2 0 -16 +

    1 0 8 19 = S1

    Q2=x = 3 1 0 8

    3 9 +

    1 3 17 = S2
    Jadi, H(x) = x2 + x
    S(x) = Q1 . S2 + S1 = -19x - 21


    BalasHapus
  4. Anonim16 Maret 2014 pukul 21.21

    P(x)=2x3 + 3x2 + 15x – 3 oleh (5x – 3)

    5x-3 => x = 3/5
    P(x) = 2x3 + 3x2 + 15x – 3

    X = 3/5 2 3 15 -3

    1 2 10 +

    2 4 17 7 = S(x)

    H(x) = 2x2 + 4x + 17
    S(x) = 7


    Peny :
    P(x) = x3 + 2x2 + 8x – 3 oleh x2 – x – 6

    Q(x) = x2 – x – 6
    (x + 2)(x – 3)
    Q1 = x+2 => x = -2
    Q2 = x-3 => x = 3

    P(x) = x3 + 2x2 + 8x -3

    Q1 = x = -2 1 2 8 -3

    -2 0 -16 +

    1 0 8 19 = S1

    Q2=x = 3 1 0 8

    3 9 +

    1 3 17 = S2
    Jadi, H(x) = x2 + x
    S(x) = Q1 . S2 + S1 = -19x - 21

    BalasHapus
  5. Unknown23 Maret 2014 pukul 21.35

    P(x)=2x3 + 3x2 + 15x – 3 oleh (5x – 3)

    5x-3 => x = 3/5
    P(x) = 2x3 + 3x2 + 15x – 3

    X = 3/5 2 3 15 -3

    1 2 10 +

    2 4 17 7 = S(x)

    H(x) = 2x2 + 4x + 17
    S(x) = 7


    Peny :
    P(x) = x3 + 2x2 + 8x – 3 oleh x2 – x – 6

    Q(x) = x2 – x – 6
    (x + 2)(x – 3)
    Q1 = x+2 => x = -2
    Q2 = x-3 => x = 3

    P(x) = x3 + 2x2 + 8x -3

    Q1 = x = -2 1 2 8 -3

    -2 0 -16 +

    1 0 8 19 = S1

    Q2=x = 3 1 0 8

    3 9 +

    1 3 17 = S2
    Jadi, H(x) = x2 + x
    S(x) = Q1 . S2 + S1 = -19x - 21

    BalasHapus
  6. Unknown23 Maret 2014 pukul 21.43

    P(x)=2x3 + 3x2 + 15x – 3 oleh (5x – 3)

    5x-3 => x = 3/5
    P(x) = 2x3 + 3x2 + 15x – 3

    X = 3/5 2 3 15 -3

    1 2 10 +

    2 4 17 7 = S(x)

    H(x) = 2x2 + 4x + 17
    S(x) = 7


    Peny :
    P(x) = x3 + 2x2 + 8x – 3 oleh x2 – x – 6

    Q(x) = x2 – x – 6
    (x + 2)(x – 3)
    Q1 = x+2 => x = -2
    Q2 = x-3 => x = 3

    P(x) = x3 + 2x2 + 8x -3

    Q1 = x = -2 1 2 8 -3

    -2 0 -16 +

    1 0 8 19 = S1

    Q2=x = 3 1 0 8

    3 9 +

    1 3 17 = S2
    Jadi, H(x) = x2 + x
    S(x) = Q1 . S2 + S1 = -19x - 21

    BalasHapus

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