Selasa, 11 Februari 2014

Tugas XI IPS 2

hitunglah nilai limit berikut
1. lim           x2 - 9
    x-> 3    akar(x + 6) - 3
2.  lim                            x          
    x-> 3    akar(9 + x) - akar (9 - x)
3.   lim           2x4 – 2x + 3
    x-> ∞           x3 + 2x - 5    
 
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8 komentar:

  1. Unknown14 Februari 2014 pukul 18.06

    Jawaban
    1.lim/(x→3) (x^2-9)/(akar(x+6)-3) x(akar(x+6)-3)/(akar(x+6)-3)
    lim/(x→3)=(x^2-9(akar(x+6)-3))/((akar x+6)-3(akar x+6)-3)
    lim/(x→3)=(x^2-9(akar x+6+3)/((akar x+6)^2-3^2 )
    lim/(x→3)=(x^2-9(x+3)(x-3)akar x+6+3)/((x+6)-9)
    lim/(x→3)=(x+3)(x-3)(akar x+6+3)/(x-3)
    =(x+3) akar x+6+3
    =3+3akar 3+6+3
    =6 akar 9+3
    =6 akar 3+3
    =6 akar 6
    =6x6
    = akar 36=6

    2.lim/(x→3)=x/(akar 9+x-akar 9-x)x(akar 9+x + akar 9+x)/█(akar 9+x +akar9+x@)
    LIM/(x-.>3)=(x(akar 9+x+akar 9+x)/((akar9+x - akar 9-x) (akar 9+x))
    =x ((akar 9+x + akar 9+x))/((akar 9+x-akar 9-x)^2)
    = x (akar 9+x+akar 9+x)/(akar 9+x-akar 9-x)
    =x(akar 9+x + akar 9+x)/(x+x)
    lim/(x→3)=(akar9+3 + akar 9+3)/3
    =(akar 12 +akar12)/3
    3.lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=x1/(x^4/(1/x^3 )) =x/(x→∞)=((2x^4-2x+3)/x^4 )/((x^3+2x-5)/x^3 )
    =lim/(x→∞)=(2- 2x)/( x^3/(1+2/█(x^2@)-5/x^3 )) +3/x^4 =(2-0+0 )/(1+0-0)=2/1 =2

    BalasHapus
  2. Unknown14 Februari 2014 pukul 18.09

    Jawaban
    1.lim/(x→3) (x^2-9)/(akar(x+6)-3) x(akar(x+6)-3)/(akar(x+6)-3)
    lim/(x→3)=(x^2-9(akar(x+6)-3))/((akar x+6)-3(akar x+6)-3)
    lim/(x→3)=(x^2-9(akar x+6+3)/((akar x+6)^2-3^2 )
    lim/(x→3)=(x^2-9(x+3)(x-3)akar x+6+3)/((x+6)-9)
    lim/(x→3)=(x+3)(x-3)(akar x+6+3)/(x-3)
    =(x+3) akar x+6+3
    =3+3akar 3+6+3
    =6 akar 9+3
    =6 akar 3+3
    =6 akar 6
    =6x6
    = akar 36=6

    2.lim/(x→3)=x/(akar 9+x-akar 9-x)x(akar 9+x + akar 9+x)/█(akar 9+x +akar9+x@)
    LIM/(x-.>3)=(x(akar 9+x+akar 9+x)/((akar9+x - akar 9-x) (akar 9+x))
    =x ((akar 9+x + akar 9+x))/((akar 9+x-akar 9-x)^2)
    = x (akar 9+x+akar 9+x)/(akar 9+x-akar 9-x)
    =x(akar 9+x + akar 9+x)/(x+x)
    lim/(x→3)=(akar9+3 + akar 9+3)/3
    =(akar 12 +akar12)/3
    3.lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=x1/(x^4/(1/x^3 )) =x/(x→∞)=((2x^4-2x+3)/x^4 )/((x^3+2x-5)/x^3 )
    =lim/(x→∞)=(2- 2x)/( x^3/(1+2/█(x^2@)-5/x^3 )) +3/x^4 =(2-0+0 )/(1+0-0)=2/1 =2

    BalasHapus
  3. Anonim14 Februari 2014 pukul 18.12

    Jawaban
    1.lim/(x→3) (x^2-9)/(akar(x+6)-3) x(akar(x+6)-3)/(akar(x+6)-3)
    lim/(x→3)=(x^2-9(akar(x+6)-3))/((akar x+6)-3(akar x+6)-3)
    lim/(x→3)=(x^2-9(akar x+6+3)/((akar x+6)^2-3^2 )
    lim/(x→3)=(x^2-9(x+3)(x-3)akar x+6+3)/((x+6)-9)
    lim/(x→3)=(x+3)(x-3)(akar x+6+3)/(x-3)
    =(x+3) akar x+6+3
    =3+3akar 3+6+3
    =6 akar 9+3
    =6 akar 3+3
    =6 akar 6
    =6x6
    = akar 36=6

    2.lim/(x→3)=x/(akar 9+x-akar 9-x)x(akar 9+x + akar 9+x)/█(akar 9+x +akar9+x@)
    LIM/(x-.>3)=(x(akar 9+x+akar 9+x)/((akar9+x - akar 9-x) (akar 9+x))
    =x ((akar 9+x + akar 9+x))/((akar 9+x-akar 9-x)^2)
    = x (akar 9+x+akar 9+x)/(akar 9+x-akar 9-x)
    =x(akar 9+x + akar 9+x)/(x+x)
    lim/(x→3)=(akar9+3 + akar 9+3)/3
    =(akar 12 +akar12)/3
    3.lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=x1/(x^4/(1/x^3 )) =x/(x→∞)=((2x^4-2x+3)/x^4 )/((x^3+2x-5)/x^3 )
    =lim/(x→∞)=(2- 2x)/( x^3/(1+2/█(x^2@)-5/x^3 )) +3/x^4 =(2-0+0 )/(1+0-0)=2/1 =2

    BalasHapus
  4. Unknown14 Februari 2014 pukul 18.15

    Jawaban
    1.lim/(x→3) (x^2-9)/(akar(x+6)-3) x(akar(x+6)-3)/(akar(x+6)-3)
    lim/(x→3)=(x^2-9(akar(x+6)-3))/((akar x+6)-3(akar x+6)-3)
    lim/(x→3)=(x^2-9(akar x+6+3)/((akar x+6)^2-3^2 )
    lim/(x→3)=(x^2-9(x+3)(x-3)akar x+6+3)/((x+6)-9)
    lim/(x→3)=(x+3)(x-3)(akar x+6+3)/(x-3)
    =(x+3) akar x+6+3
    =3+3akar 3+6+3
    =6 akar 9+3
    =6 akar 3+3
    =6 akar 6
    =6x6
    = akar 36=6

    2.lim/(x→3)=x/(akar 9+x-akar 9-x)x(akar 9+x + akar 9+x)/█(akar 9+x +akar9+x@)
    LIM/(x-.>3)=(x(akar 9+x+akar 9+x)/((akar9+x - akar 9-x) (akar 9+x))
    =x ((akar 9+x + akar 9+x))/((akar 9+x-akar 9-x)^2)
    = x (akar 9+x+akar 9+x)/(akar 9+x-akar 9-x)
    =x(akar 9+x + akar 9+x)/(x+x)
    lim/(x→3)=(akar9+3 + akar 9+3)/3
    =(akar 12 +akar12)/3
    3.lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=x1/(x^4/(1/x^3 )) =x/(x→∞)=((2x^4-2x+3)/x^4 )/((x^3+2x-5)/x^3 )
    =lim/(x→∞)=(2- 2x)/( x^3/(1+2/█(x^2@)-5/x^3 )) +3/x^4 =(2-0+0 )/(1+0-0)=2/1 =2

    BalasHapus
  5. Unknown14 Februari 2014 pukul 18.21

    Jawaban
    1.lim/(x→3) (x^2-9)/(akar(x+6)-3) x(akar(x+6)-3)/(akar(x+6)-3)
    lim/(x→3)=(x^2-9(akar(x+6)-3))/((akar x+6)-3(akar x+6)-3)
    lim/(x→3)=(x^2-9(akar x+6+3)/((akar x+6)^2-3^2 )
    lim/(x→3)=(x^2-9(x+3)(x-3)akar x+6+3)/((x+6)-9)
    lim/(x→3)=(x+3)(x-3)(akar x+6+3)/(x-3)
    =(x+3) akar x+6+3
    =3+3akar 3+6+3
    =6 akar 9+3
    =6 akar 3+3
    =6 akar 6
    =6x6
    = akar 36=6

    2.lim/(x→3)=x/(akar 9+x-akar 9-x)x(akar 9+x + akar 9+x)/█(akar 9+x +akar9+x@)
    LIM/(x-.>3)=(x(akar 9+x+akar 9+x)/((akar9+x - akar 9-x) (akar 9+x))
    =x ((akar 9+x + akar 9+x))/((akar 9+x-akar 9-x)^2)
    = x (akar 9+x+akar 9+x)/(akar 9+x-akar 9-x)
    =x(akar 9+x + akar 9+x)/(x+x)
    lim/(x→3)=(akar9+3 + akar 9+3)/3
    =(akar 12 +akar12)/3
    3.lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=x1/(x^4/(1/x^3 )) =x/(x→∞)=((2x^4-2x+3)/x^4 )/((x^3+2x-5)/x^3 )
    =lim/(x→∞)=(2- 2x)/( x^3/(1+2/█(x^2@)-5/x^3 )) +3/x^4 =(2-0+0 )/(1+0-0)=2/1 =2

    BalasHapus
  6. Unknown14 Februari 2014 pukul 18.24

    Jawaban
    1.lim/(x→3) (x^2-9)/(akar(x+6)-3) x(akar(x+6)-3)/(akar(x+6)-3)
    lim/(x→3)=(x^2-9(akar(x+6)-3))/((akar x+6)-3(akar x+6)-3)
    lim/(x→3)=(x^2-9(akar x+6+3)/((akar x+6)^2-3^2 )
    lim/(x→3)=(x^2-9(x+3)(x-3)akar x+6+3)/((x+6)-9)
    lim/(x→3)=(x+3)(x-3)(akar x+6+3)/(x-3)
    =(x+3) akar x+6+3
    =3+3akar 3+6+3
    =6 akar 9+3
    =6 akar 3+3
    =6 akar 6
    =6x6
    = akar 36=6

    2.lim/(x→3)=x/(akar 9+x-akar 9-x)x(akar 9+x + akar 9+x)/█(akar 9+x +akar9+x@)
    LIM/(x-.>3)=(x(akar 9+x+akar 9+x)/((akar9+x - akar 9-x) (akar 9+x))
    =x ((akar 9+x + akar 9+x))/((akar 9+x-akar 9-x)^2)
    = x (akar 9+x+akar 9+x)/(akar 9+x-akar 9-x)
    =x(akar 9+x + akar 9+x)/(x+x)
    lim/(x→3)=(akar9+3 + akar 9+3)/3
    =(akar 12 +akar12)/3
    3.lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=x1/(x^4/(1/x^3 )) =x/(x→∞)=((2x^4-2x+3)/x^4 )/((x^3+2x-5)/x^3 )
    =lim/(x→∞)=(2- 2x)/( x^3/(1+2/█(x^2@)-5/x^3 )) +3/x^4 =(2-0+0 )/(1+0-0)=2/1 =2

    BalasHapus
  7. Unknown14 Februari 2014 pukul 19.20

    Jawaban
    1.lim/(x→3) (x^2-9)/(akar(x+6)-3) x(akar(x+6)-3)/(akar(x+6)-3)
    lim/(x→3)=(x^2-9(akar(x+6)-3))/((akar x+6)-3(akar x+6)-3)
    lim/(x→3)=(x^2-9(akar x+6+3)/((akar x+6)^2-3^2 )
    lim/(x→3)=(x^2-9(x+3)(x-3)akar x+6+3)/((x+6)-9)
    lim/(x→3)=(x+3)(x-3)(akar x+6+3)/(x-3)
    =(x+3) akar x+6+3
    =3+3akar 3+6+3
    =6 akar 9+3
    =6 akar 3+3
    =6 akar 6
    =6x6
    = akar 36=6

    2.lim/(x→3)=x/(akar 9+x-akar 9-x)x(akar 9+x + akar 9+x)/█(akar 9+x +akar9+x@)
    LIM/(x-.>3)=(x(akar 9+x+akar 9+x)/((akar9+x - akar 9-x) (akar 9+x))
    =x ((akar 9+x + akar 9+x))/((akar 9+x-akar 9-x)^2)
    = x (akar 9+x+akar 9+x)/(akar 9+x-akar 9-x)
    =x(akar 9+x + akar 9+x)/(x+x)
    lim/(x→3)=(akar9+3 + akar 9+3)/3
    =(akar 12 +akar12)/3
    3.lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=x1/(x^4/(1/x^3 )) =x/(x→∞)=((2x^4-2x+3)/x^4 )/((x^3+2x-5)/x^3 )
    =lim/(x→∞)=(2- 2x)/( x^3/(1+2/█(x^2@)-5/x^3 )) +3/x^4 =(2-0+0 )/(1+0-0)=2/1 =2

    BalasHapus
  8. Unknown14 Februari 2014 pukul 19.47

    Jawaban
    1.lim/(x→3) (x^2-9)/(akar(x+6)-3) x(akar(x+6)-3)/(akar(x+6)-3)
    lim/(x→3)=(x^2-9(akar(x+6)-3))/((akar x+6)-3(akar x+6)-3)
    lim/(x→3)=(x^2-9(akar x+6+3)/((akar x+6)^2-3^2 )
    lim/(x→3)=(x^2-9(x+3)(x-3)akar x+6+3)/((x+6)-9)
    lim/(x→3)=(x+3)(x-3)(akar x+6+3)/(x-3)
    =(x+3) akar x+6+3
    =3+3akar 3+6+3
    =6 akar 9+3
    =6 akar 3+3
    =6 akar 6
    =6x6
    = akar 36=6

    2.lim/(x→3)=x/(akar 9+x-akar 9-x)x(akar 9+x + akar 9+x)/█(akar 9+x +akar9+x@)
    LIM/(x-.>3)=(x(akar 9+x+akar 9+x)/((akar9+x - akar 9-x) (akar 9+x))
    =x ((akar 9+x + akar 9+x))/((akar 9+x-akar 9-x)^2)
    = x (akar 9+x+akar 9+x)/(akar 9+x-akar 9-x)
    =x(akar 9+x + akar 9+x)/(x+x)
    lim/(x→3)=(akar9+3 + akar 9+3)/3
    =(akar 12 +akar12)/3
    3.lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=lim/(x→∞)=(2x^4-2x+3)/(x^3+2x-5)=x1/(x^4/(1/x^3 )) =x/(x→∞)=((2x^4-2x+3)/x^4 )/((x^3+2x-5)/x^3 )
    =lim/(x→∞)=(2- 2x)/( x^3/(1+2/█(x^2@)-5/x^3 )) +3/x^4 =(2-0+0 )/(1+0-0)=2/1 =2

    BalasHapus

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