Kamis, 20 Februari 2014

Tugas XI IPA 1



11.       Tentukan nilai p, jika di ketahui f(x) = 5x3 – 2px2 + 3x – 3p di bagi (x – 3) mempunyai sisa 283
22.       Tentukan sisa pembagian f(x) = 4x4 + 5x – 3x + 10 dibagi (2x2 + x – 1)

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19 komentar:

  1. Anonim24 Februari 2014 pukul 19.00

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25

    BalasHapus
  2. Unknown24 Februari 2014 pukul 19.03

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25



    BalasHapus
  3. Unknown24 Februari 2014 pukul 19.08

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25

    BalasHapus
  4. Unknown24 Februari 2014 pukul 19.08

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25



    BalasHapus
  5. Unknown24 Februari 2014 pukul 19.12

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25

    BalasHapus
  6. Unknown24 Februari 2014 pukul 19.17

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25



    BalasHapus
  7. Unknown24 Februari 2014 pukul 19.17

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25

    BalasHapus
  8. Unknown24 Februari 2014 pukul 19.20

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25

    BalasHapus
  9. Unknown24 Februari 2014 pukul 19.20

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25

    BalasHapus
  10. Unknown24 Februari 2014 pukul 19.23

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25

    BalasHapus
  11. Unknown24 Februari 2014 pukul 19.24

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25

    BalasHapus
  12. Unknown24 Februari 2014 pukul 19.28

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25

    BalasHapus
  13. Unknown24 Februari 2014 pukul 19.33

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25

    BalasHapus
  14. Unknown24 Februari 2014 pukul 19.35

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25



    BalasHapus
  15. Unknown24 Februari 2014 pukul 19.42

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25

    BalasHapus
  16. Unknown24 Maret 2014 pukul 18.50

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25

    BalasHapus
  17. Anonim24 Maret 2014 pukul 18.55

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25

    BalasHapus
  18. Unknown24 Maret 2014 pukul 19.48

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25

    BalasHapus
  19. Unknown17 Juli 2014 pukul 19.03

    Penyelesaian :
    1. F(x) = 5x3-2px2+3x-3p = 283
    = 5(3)3-3p(3)2+3(3) – 3p
    = 135-18p+9 -3p
    = 144-21p = 283
    21p = 283-144 = 139
    P = 139/21 = 6,19


    2. F(x) = 4x4+5x-3x+10
    Q(x) = (2x2+x-1)
    = (x+1)(2x-1)
    Q1 = x+1 => x = -1
    Q2 = 2x-1 => x = 1/2

    # 4x4 + 0x3 + 0x2 + 5x – 3x + 10
    4 0 0 5 -3 10
    x= -1 -4 4 -4 -1 4 +

    4 -4 4 1 -4 14 = s1

    # x= 1/2 2 -1 1,5 1,25

    4 -2 3 2,5 -2,75 = S2


    H(x) = 4x2 – 2x + 3
    S(x) = Q1 X S2 + S1
    = (x+1) -2,75 + 14
    = -2,75x - 2,75 + 14
    = -2,75x - 11,25


    BalasHapus

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