Selasa, 19 Agustus 2014

Tugas Ketiga XII IPA 1



1.       Tentukan y = F(x), apabila dy/dx = 3x2 – 7, dan F(3) = 15
2.       Tentukan integral fungsi trigonometri berikut
a.       Integral 7 sec2 x dx
b.      Integral -5 sin x dx

3 komentar:

  1. ¤F1(x)=dy/dx= 3x2-7
    F(x)=S3x2-7
    F(x)=X3- 7x + C
    F(3)=15 X3-7x+C=15
    (3)3-7(3)+C=15
    27-21+C=15
    6+C=15 C=9
    F(x)= X3-7x+9

    a) S 7 sec2 X dx =7 S
    sec2 x dx = 7 (tan x) + C =7tan x +C

    b) S -5 sin X dx = -5 S sin x dx = -5 (-cos x) + C = 5 cos x + C

    BalasHapus
  2. ¤F1(x)=dy/dx= 3x2-7
    F(x)=S3x2-7
    F(x)=X3- 7x + C
    F(3)=15 X3-7x+C=15
    (3)3-7(3)+C=15
    27-21+C=15
    6+C=15 C=9
    F(x)= X3-7x+9

    a) S 7 sec2 X dx =7 S
    sec2 x dx = 7 (tan x) + C =7tan x +C

    b) S -5 sin X dx = -5 S sin x dx = -5 (-cos x) + C = 5 cos x + C

    BalasHapus
  3. ¤F1(x)=dy/dx= 3x2-7
    F(x)=S3x2-7
    F(x)=X3- 7x + C
    F(3)=15 X3-7x+C=15
    (3)3-7(3)+C=15
    27-21+C=15
    6+C=15 C=9
    F(x)= X3-7x+9

    a) S 7 sec2 X dx =7 S
    sec2 x dx = 7 (tan x) + C =7tan x +C

    b) S -5 sin X dx = -5 S sin x dx = -5 (-cos x) + C = 5 cos x + C

    BalasHapus