Jumat, 22 Agustus 2014

Tugas Keempat XII IPA 1



Tentukan integral tentu berikut
1.       Integral (5x pangkat 5 + 3x) dx dengan batas [-2, 3]
2.       Integral (x pangkat 6 + x) dx dengan batas [2, 5]
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10 komentar:

  1. Unknown24 Agustus 2014 pukul 00.04

    A. S3 _2 (5x5 + 3x) dx
    =[5/6 x6 + 3/2 x2]3 _2
    =[5/6(3)6 + 3/2(3)2] - [5/6(-2)6 + 3/2(-2)2]
    =[5/6(729) + 3/2(9)] - [5/6(64) + 3/2(4)]
    =[3645/6 + 27/2] - [320/6 + 12/2]
    =[3645+81/6] - [320+36/6]
    =3726/6 - 356/6
    =3370/6
    =561 4/6

    B. S5 2 (x6 + x) dx
    =[1/7x7 + 1/2x2]
    =[1/7(5)7 + 1/2(5)2] - (1/7(2)7 +1/2(2)2]
    =[1/7(78125) + 1/2(25)] - [1/7(128)+1/2(4)]
    =[78125/7 + 25/2] - [128/7+4/2]
    =[156250+175/14] - [256+28/14]
    =156425/14 + 84/14
    =156509/14
    =11179 3/14

    BalasHapus
  2. Anonim24 Agustus 2014 pukul 06.10

    A. S3 _2 (5x5 + 3x) dx
    =[5/6 x6 + 3/2 x2]3 _2
    =[5/6(3)6 + 3/2(3)2] - [5/6(-2)6 + 3/2(-2)2]
    =[5/6(729) + 3/2(9)] - [5/6(64) + 3/2(4)]
    =[3645/6 + 27/2] - [320/6 + 12/2]
    =[3645+81/6] - [320+36/6]
    =3726/6 - 356/6
    =3370/6
    =561 4/6

    B. S5 2 (x6 + x) dx
    =[1/7x7 + 1/2x2]
    =[1/7(5)7 + 1/2(5)2] - (1/7(2)7 +1/2(2)2]
    =[1/7(78125) + 1/2(25)] - [1/7(128)+1/2(4)]
    =[78125/7 + 25/2] - [128/7+4/2]
    =[156250+175/14] - [256+28/14]
    =156425/14 + 84/14
    =156509/14
    =11179 3/14

    BalasHapus
  3. Unknown24 Agustus 2014 pukul 16.12

    A. S3 _2 (5x5 + 3x) dx
    =[5/6 x6 + 3/2 x2]3 _2
    =[5/6(3)6 + 3/2(3)2] - [5/6(-2)6 + 3/2(-2)2]
    =[5/6(729) + 3/2(9)] - [5/6(64) + 3/2(4)]
    =[3645/6 + 27/2] - [320/6 + 12/2]
    =[3645+81/6] - [320+36/6]
    =3726/6 - 356/6
    =3370/6
    =561 4/6

    B. S5 2 (x6 + x) dx
    =[1/7x7 + 1/2x2]
    =[1/7(5)7 + 1/2(5)2] - (1/7(2)7 +1/2(2)2]
    =[1/7(78125) + 1/2(25)] - [1/7(128)+1/2(4)]
    =[78125/7 + 25/2] - [128/7+4/2]
    =[156250+175/14] - [256+28/14]
    =156425/14 + 84/14
    =156509/14
    =11179 3/14

    BalasHapus
  4. Unknown24 Agustus 2014 pukul 16.22

    A. S3 _2 (5x5 + 3x) dx
    =[5/6 x6 + 3/2 x2]3 _2
    =[5/6(3)6 + 3/2(3)2] - [5/6(-2)6 + 3/2(-2)2]
    =[5/6(729) + 3/2(9)] - [5/6(64) + 3/2(4)]
    =[3645/6 + 27/2] - [320/6 + 12/2]
    =[3645+81/6] - [320+36/6]
    =3726/6 - 356/6
    =3370/6
    =561 4/6

    B. S5 2 (x6 + x) dx
    =[1/7x7 + 1/2x2]
    =[1/7(5)7 + 1/2(5)2] - (1/7(2)7 +1/2(2)2]
    =[1/7(78125) + 1/2(25)] - [1/7(128)+1/2(4)]
    =[78125/7 + 25/2] - [128/7+4/2]
    =[156250+175/14] - [256+28/14]
    =156425/14 + 84/14
    =156509/14
    =11179 3/14

    BalasHapus
  5. Unknown25 Agustus 2014 pukul 00.18

    A. S3 _2 (5x5 + 3x) dx
    =[5/6 x6 + 3/2 x2]3 _2
    =[5/6(3)6 + 3/2(3)2] - [5/6(-2)6 + 3/2(-2)2]
    =[5/6(729) + 3/2(9)] - [5/6(64) + 3/2(4)]
    =[3645/6 + 27/2] - [320/6 + 12/2]
    =[3645+81/6] - [320+36/6]
    =3726/6 - 356/6
    =3370/6
    =561 4/6

    B. S5 2 (x6 + x) dx
    =[1/7x7 + 1/2x2]
    =[1/7(5)7 + 1/2(5)2] - (1/7(2)7 +1/2(2)2]
    =[1/7(78125) + 1/2(25)] - [1/7(128)+1/2(4)]
    =[78125/7 + 25/2] - [128/7+4/2]
    =[156250+175/14] - [256+28/14]
    =156425/14 + 84/14
    =156509/14
    =11179 3/14

    BalasHapus
  6. Unknown25 Agustus 2014 pukul 03.55

    A. S3 _2 (5x5 + 3x) dx
    =[5/6 x6 + 3/2 x2]3 _2
    =[5/6(3)6 + 3/2(3)2] - [5/6(-2)6 + 3/2(-2)2]
    =[5/6(729) + 3/2(9)] - [5/6(64) + 3/2(4)]
    =[3645/6 + 27/2] - [320/6 + 12/2]
    =[3645+81/6] - [320+36/6]
    =3726/6 - 356/6
    =3370/6
    =561 4/6

    B. S5 2 (x6 + x) dx
    =[1/7x7 + 1/2x2]
    =[1/7(5)7 + 1/2(5)2] - (1/7(2)7 +1/2(2)2]
    =[1/7(78125) + 1/2(25)] - [1/7(128)+1/2(4)]
    =[78125/7 + 25/2] - [128/7+4/2]
    =[156250+175/14] - [256+28/14]
    =156425/14 + 84/14
    =156509/14
    =11179 3/14

    BalasHapus
  7. Unknown25 Agustus 2014 pukul 04.03

    A. S3 _2 (5x5 + 3x) dx
    =[5/6 x6 + 3/2 x2]3 _2
    =[5/6(3)6 + 3/2(3)2] - [5/6(-2)6 + 3/2(-2)2]
    =[5/6(729) + 3/2(9)] - [5/6(64) + 3/2(4)]
    =[3645/6 + 27/2] - [320/6 + 12/2]
    =[3645+81/6] - [320+36/6]
    =3726/6 - 356/6
    =3370/6
    =561 4/6

    B. S5 2 (x6 + x) dx
    =[1/7x7 + 1/2x2]
    =[1/7(5)7 + 1/2(5)2] - (1/7(2)7 +1/2(2)2]
    =[1/7(78125) + 1/2(25)] - [1/7(128)+1/2(4)]
    =[78125/7 + 25/2] - [128/7+4/2]
    =[156250+175/14] - [256+28/14]
    =156425/14 + 84/14
    =156509/14
    =11179 3/14

    BalasHapus
  8. Unknown25 Agustus 2014 pukul 04.14

    A. S3 _2 (5x5 + 3x) dx
    =[5/6 x6 + 3/2 x2]3 _2
    =[5/6(3)6 + 3/2(3)2] - [5/6(-2)6 + 3/2(-2)2]
    =[5/6(729) + 3/2(9)] - [5/6(64) + 3/2(4)]
    =[3645/6 + 27/2] - [320/6 + 12/2]
    =[3645+81/6] - [320+36/6]
    =3726/6 - 356/6
    =3370/6
    =561 4/6

    B. S5 2 (x6 + x) dx
    =[1/7x7 + 1/2x2]
    =[1/7(5)7 + 1/2(5)2] - (1/7(2)7 +1/2(2)2]
    =[1/7(78125) + 1/2(25)] - [1/7(128)+1/2(4)]
    =[78125/7 + 25/2] - [128/7+4/2]
    =[156250+175/14] - [256+28/14]
    =156425/14 + 84/14
    =156509/14
    =11179 3/14

    BalasHapus
  9. Unknown25 Agustus 2014 pukul 04.26

    A. S3 _2 (5x5 + 3x) dx
    =[5/6 x6 + 3/2 x2]3 _2
    =[5/6(3)6 + 3/2(3)2] - [5/6(-2)6 + 3/2(-2)2]
    =[5/6(729) + 3/2(9)] - [5/6(64) + 3/2(4)]
    =[3645/6 + 27/2] - [320/6 + 12/2]
    =[3645+81/6] - [320+36/6]
    =3726/6 - 356/6
    =3370/6
    =561 4/6

    B. S5 2 (x6 + x) dx
    =[1/7x7 + 1/2x2]
    =[1/7(5)7 + 1/2(5)2] - (1/7(2)7 +1/2(2)2]
    =[1/7(78125) + 1/2(25)] - [1/7(128)+1/2(4)]
    =[78125/7 + 25/2] - [128/7+4/2]
    =[156250+175/14] - [256+28/14]
    =156425/14 + 84/14
    =156509/14
    =11179 3/14

    BalasHapus
  10. Unknown25 Agustus 2014 pukul 07.41

    sampe dpe titik koma sama samua

    BalasHapus

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