Rabu, 29 Januari 2014

Tugas XI IPA 1 SMA Negeri 1 Bolaang



Tentukan bentuk umum persamaan singgung pada tiap lingkaran dan melalui titik yang diberikan berikut ini . .
1.      L : x2 + (y – 2)2 = 4; yang berabsis -3
2.      L : (x – 2)2 + (y + 1)2 = 4; yang berordinat -1
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8 komentar:

  1. Unknown3 Februari 2014 pukul 18.07

    Belum ada yang b kirim tugas ekh, mantp memang

    BalasHapus
  2. Unknown3 Februari 2014 pukul 18.19

    Nama : Yanderson Mintamanis
    Jawaban :
    1. L= X2 + (Y-2)2=4
    Peny.
    • mencari titik potong Y
    X = -3 ≡ -32 + (y-2)2= 4
    9 + y -2 = 2
    y-2 = -7
    y1 = -5
    T(-3,-5)
    • (x1-a)(x-a) + (y1-b)(y-b) = 4
    • (x1-a)(x-a) + (y1+2)(y+2) = 4
    • (-3-a)(x-a) + (-5+2)(y+2) = 4
    • -3a (x-a) -3 (y+2) = 4
    • -3ax – 3a2- 3y – 6 = 4
    • -3 ax – 3a2-3y = 10

    2. L: (x-2)2 + (y+1)2 = 4
    • Mencari titik potong X
    Y= -1 ≡ (x-2)2 + (-1+1)2= 4
    (x-2)2 = 4
    X – 2 = 4
    x- 2 = 2
    x= 4

    T(4,-1)
    • (x1-(-2)) (x-(-2)) + (y1-1) (y-1) = 4
    • (4 + 2) (x+2) + (-1-1) (y-1) = 4
    • 6 (x + 2) – 2 (y-1) = 4
    • 6x + 12 – 2y + 2 = 4
    • 6x – 2y = -10







    BalasHapus
  3. Anonim24 Maret 2014 pukul 18.22

    Jawaban :
    1. L= X2 + (Y-2)2=4
    Peny.
    • mencari titik potong Y
    X = -3 ≡ -32 + (y-2)2= 4
    9 + y -2 = 2
    y-2 = -7
    y1 = -5
    T(-3,-5)
    • (x1-a)(x-a) + (y1-b)(y-b) = 4
    • (x1-a)(x-a) + (y1+2)(y+2) = 4
    • (-3-a)(x-a) + (-5+2)(y+2) = 4
    • -3a (x-a) -3 (y+2) = 4
    • -3ax – 3a2- 3y – 6 = 4
    • -3 ax – 3a2-3y = 10

    2. L: (x-2)2 + (y+1)2 = 4
    • Mencari titik potong X
    Y= -1 ≡ (x-2)2 + (-1+1)2= 4
    (x-2)2 = 4
    X – 2 = 4
    x- 2 = 2
    x= 4

    T(4,-1)
    • (x1-(-2)) (x-(-2)) + (y1-1) (y-1) = 4
    • (4 + 2) (x+2) + (-1-1) (y-1) = 4
    • 6 (x + 2) – 2 (y-1) = 4
    • 6x + 12 – 2y + 2 = 4
    • 6x – 2y = -10

    BalasHapus
  4. Unknown24 Maret 2014 pukul 18.49

    Jawaban :
    1. L= X2 + (Y-2)2=4
    Peny.
    • mencari titik potong Y
    X = -3 ≡ -32 + (y-2)2= 4
    9 + y -2 = 2
    y-2 = -7
    y1 = -5
    T(-3,-5)
    • (x1-a)(x-a) + (y1-b)(y-b) = 4
    • (x1-a)(x-a) + (y1+2)(y+2) = 4
    • (-3-a)(x-a) + (-5+2)(y+2) = 4
    • -3a (x-a) -3 (y+2) = 4
    • -3ax – 3a2- 3y – 6 = 4
    • -3 ax – 3a2-3y = 10

    2. L: (x-2)2 + (y+1)2 = 4
    • Mencari titik potong X
    Y= -1 ≡ (x-2)2 + (-1+1)2= 4
    (x-2)2 = 4
    X – 2 = 4
    x- 2 = 2
    x= 4

    T(4,-1)
    • (x1-(-2)) (x-(-2)) + (y1-1) (y-1) = 4
    • (4 + 2) (x+2) + (-1-1) (y-1) = 4
    • 6 (x + 2) – 2 (y-1) = 4
    • 6x + 12 – 2y + 2 = 4
    • 6x – 2y = -10

    BalasHapus
  5. Anonim24 Maret 2014 pukul 18.53

    Jawaban :
    1. L= X2 + (Y-2)2=4
    Peny.
    • mencari titik potong Y
    X = -3 ≡ -32 + (y-2)2= 4
    9 + y -2 = 2
    y-2 = -7
    y1 = -5
    T(-3,-5)
    • (x1-a)(x-a) + (y1-b)(y-b) = 4
    • (x1-a)(x-a) + (y1+2)(y+2) = 4
    • (-3-a)(x-a) + (-5+2)(y+2) = 4
    • -3a (x-a) -3 (y+2) = 4
    • -3ax – 3a2- 3y – 6 = 4
    • -3 ax – 3a2-3y = 10

    2. L: (x-2)2 + (y+1)2 = 4
    • Mencari titik potong X
    Y= -1 ≡ (x-2)2 + (-1+1)2= 4
    (x-2)2 = 4
    X – 2 = 4
    x- 2 = 2
    x= 4

    T(4,-1)
    • (x1-(-2)) (x-(-2)) + (y1-1) (y-1) = 4
    • (4 + 2) (x+2) + (-1-1) (y-1) = 4
    • 6 (x + 2) – 2 (y-1) = 4
    • 6x + 12 – 2y + 2 = 4
    • 6x – 2y = -10

    BalasHapus
  6. Unknown24 Maret 2014 pukul 18.53

    Jawaban :
    1. L= X2 + (Y-2)2=4
    Peny.
    • mencari titik potong Y
    X = -3 ≡ -32 + (y-2)2= 4
    9 + y -2 = 2
    y-2 = -7
    y1 = -5
    T(-3,-5)
    • (x1-a)(x-a) + (y1-b)(y-b) = 4
    • (x1-a)(x-a) + (y1+2)(y+2) = 4
    • (-3-a)(x-a) + (-5+2)(y+2) = 4
    • -3a (x-a) -3 (y+2) = 4
    • -3ax – 3a2- 3y – 6 = 4
    • -3 ax – 3a2-3y = 10

    2. L: (x-2)2 + (y+1)2 = 4
    • Mencari titik potong X
    Y= -1 ≡ (x-2)2 + (-1+1)2= 4
    (x-2)2 = 4
    X – 2 = 4
    x- 2 = 2
    x= 4

    T(4,-1)
    • (x1-(-2)) (x-(-2)) + (y1-1) (y-1) = 4
    • (4 + 2) (x+2) + (-1-1) (y-1) = 4
    • 6 (x + 2) – 2 (y-1) = 4
    • 6x + 12 – 2y + 2 = 4
    • 6x – 2y = -10


    BalasHapus
  7. Unknown24 Maret 2014 pukul 19.23

    Jawaban :
    1. L= X2 + (Y-2)2=4
    Peny.
    • mencari titik potong Y
    X = -3 ≡ -32 + (y-2)2= 4
    9 + y -2 = 2
    y-2 = -7
    y1 = -5
    T(-3,-5)
    • (x1-a)(x-a) + (y1-b)(y-b) = 4
    • (x1-a)(x-a) + (y1+2)(y+2) = 4
    • (-3-a)(x-a) + (-5+2)(y+2) = 4
    • -3a (x-a) -3 (y+2) = 4
    • -3ax – 3a2- 3y – 6 = 4
    • -3 ax – 3a2-3y = 10

    2. L: (x-2)2 + (y+1)2 = 4
    • Mencari titik potong X
    Y= -1 ≡ (x-2)2 + (-1+1)2= 4
    (x-2)2 = 4
    X – 2 = 4
    x- 2 = 2
    x= 4

    T(4,-1)
    • (x1-(-2)) (x-(-2)) + (y1-1) (y-1) = 4
    • (4 + 2) (x+2) + (-1-1) (y-1) = 4
    • 6 (x + 2) – 2 (y-1) = 4
    • 6x + 12 – 2y + 2 = 4
    • 6x – 2y = -10

    BalasHapus
  8. Anonim24 Maret 2014 pukul 19.25

    Jawaban :
    1. L= X2 + (Y-2)2=4
    Peny.
    • mencari titik potong Y
    X = -3 ≡ -32 + (y-2)2= 4
    9 + y -2 = 2
    y-2 = -7
    y1 = -5
    T(-3,-5)
    • (x1-a)(x-a) + (y1-b)(y-b) = 4
    • (x1-a)(x-a) + (y1+2)(y+2) = 4
    • (-3-a)(x-a) + (-5+2)(y+2) = 4
    • -3a (x-a) -3 (y+2) = 4
    • -3ax – 3a2- 3y – 6 = 4
    • -3 ax – 3a2-3y = 10

    2. L: (x-2)2 + (y+1)2 = 4
    • Mencari titik potong X
    Y= -1 ≡ (x-2)2 + (-1+1)2= 4
    (x-2)2 = 4
    X – 2 = 4
    x- 2 = 2
    x= 4

    T(4,-1)
    • (x1-(-2)) (x-(-2)) + (y1-1) (y-1) = 4
    • (4 + 2) (x+2) + (-1-1) (y-1) = 4
    • 6 (x + 2) – 2 (y-1) = 4
    • 6x + 12 – 2y + 2 = 4
    • 6x – 2y = -10

    BalasHapus

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