Kamis, 24 April 2014

Tugas XI IPA 1



1.       Diketahui f(x)  = 3x + 1 dan g(x) = (x – 1) / (2x + 3), tentukan (f o g)-1(x)
2.       Tentukan limit dari (x2 – 9) / (x – 3) untuk x mendekati 3
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10 komentar:

  1. Unknown27 April 2014 pukul 21.09

    a. F(x) = 3x + 1
    G(x) = (x-1)/(x-3)
    (fOg)-1 = f(g(x))
    = f((x-1)/(x-3))
    = 3((x-1)/(x-3))+ 1
    = (3x-3)/(3x-9) + 1
    = (3x-3)/(3x-9) + (3x-9)/(3x-9)
    = (6x-12)/(3x-9)
    = (2x-12)/(-9)

    b. Lim (x2-9)/(x-3) = Lim (x-3)(x+3)/(x-3)1
    x 3 x 3
    Lim = ((x+3))/1
    X 3= (3+3)/1 = 6/1 = 6

    BalasHapus
  2. Anonim27 April 2014 pukul 21.15

    a. F(x) = 3x + 1
    G(x) = (x-1)/(x-3)
    (fOg)-1 = f(g(x))
    = f((x-1)/(x-3))
    = 3((x-1)/(x-3))+ 1
    = (3x-3)/(3x-9) + 1
    = (3x-3)/(3x-9) + (3x-9)/(3x-9)
    = (6x-12)/(3x-9)
    = (2x-12)/(-9)

    b. Lim (x2-9)/(x-3) = Lim (x-3)(x+3)/(x-3)1
    x 3 x 3
    Lim = ((x+3))/1
    X 3= (3+3)/1 = 6/1 = 6

    BalasHapus
  3. Unknown27 April 2014 pukul 21.19

    a. F(x) = 3x + 1
    G(x) = (x-1)/(x-3)
    (fOg)-1 = f(g(x))
    = f((x-1)/(x-3))
    = 3((x-1)/(x-3))+ 1
    = (3x-3)/(3x-9) + 1
    = (3x-3)/(3x-9) + (3x-9)/(3x-9)
    = (6x-12)/(3x-9)
    = (2x-12)/(-9)

    b. Lim (x2-9)/(x-3) = Lim (x-3)(x+3)/(x-3)1
    x 3 x 3
    Lim = ((x+3))/1
    X 3= (3+3)/1 = 6/1 = 6

    BalasHapus
  4. Unknown27 April 2014 pukul 21.25

    a. F(x) = 3x + 1
    G(x) = (x-1)/(x-3)
    (fOg)-1 = f(g(x))
    = f((x-1)/(x-3))
    = 3((x-1)/(x-3))+ 1
    = (3x-3)/(3x-9) + 1
    = (3x-3)/(3x-9) + (3x-9)/(3x-9)
    = (6x-12)/(3x-9)
    = (2x-12)/(-9)

    b. Lim (x2-9)/(x-3) = Lim (x-3)(x+3)/(x-3)1
    x 3 x 3
    Lim = ((x+3))/1
    X 3= (3+3)/1 = 6/1 = 6

    BalasHapus
  5. Unknown27 April 2014 pukul 21.30

    a. F(x) = 3x + 1
    G(x) = (x-1)/(x-3)
    (fOg)-1 = f(g(x))
    = f((x-1)/(x-3))
    = 3((x-1)/(x-3))+ 1
    = (3x-3)/(3x-9) + 1
    = (3x-3)/(3x-9) + (3x-9)/(3x-9)
    = (6x-12)/(3x-9)
    = (2x-12)/(-9)

    b. Lim (x2-9)/(x-3) = Lim (x-3)(x+3)/(x-3)1
    x 3 x 3
    Lim = ((x+3))/1
    X 3= (3+3)/1 = 6/1 = 6

    BalasHapus
  6. Unknown27 April 2014 pukul 21.48

    a. F(x) = 3x + 1
    G(x) = (x-1)/(x-3)
    (fOg)-1 = f(g(x))
    = f((x-1)/(x-3))
    = 3((x-1)/(x-3))+ 1
    = (3x-3)/(3x-9) + 1
    = (3x-3)/(3x-9) + (3x-9)/(3x-9)
    = (6x-12)/(3x-9)
    = (2x-12)/(-9)

    b. Lim (x2-9)/(x-3) = Lim (x-3)(x+3)/(x-3)1
    x 3 x 3
    Lim = ((x+3))/1
    X 3= (3+3)/1 = 6/1 = 6

    BalasHapus
  7. Anonim27 April 2014 pukul 21.55

    F(x) = 3x + 1
    G(x) = (x-1)/(x-3)
    (fOg)-1 = f(g(x))
    = f((x-1)/(x-3))
    = 3((x-1)/(x-3))+ 1
    = (3x-3)/(3x-9) + 1
    = (3x-3)/(3x-9) + (3x-9)/(3x-9)
    = (6x-12)/(3x-9)
    = (2x-12)/(-9)

    Lim (x2-9)/(x-3) = Lim (x-3)(x+3)/(x-3)1
    x 3 x 3
    Lim = ((x+3))/1
    X 3= (3+3)/1 = 6/1 = 6

    BalasHapus
  8. Unknown27 April 2014 pukul 22.10

    F(x) = 3x + 1
    G(x) = (x-1)/(x-3)
    (fOg)-1 = f(g(x))
    = f((x-1)/(x-3))
    = 3((x-1)/(x-3))+ 1
    = (3x-3)/(3x-9) + 1
    = (3x-3)/(3x-9) + (3x-9)/(3x-9)
    = (6x-12)/(3x-9)
    = (2x-12)/(-9)

    Lim (x2-9)/(x-3) = Lim (x-3)(x+3)/(x-3)1
    x 3 x 3
    Lim = ((x+3))/1
    X 3= (3+3)/1 = 6/1 = 6

    BalasHapus
  9. Unknown27 April 2014 pukul 22.14

    F(x) = 3x + 1
    G(x) = (x-1)/(x-3)
    (fOg)-1 = f(g(x))
    = f((x-1)/(x-3))
    = 3((x-1)/(x-3))+ 1
    = (3x-3)/(3x-9) + 1
    = (3x-3)/(3x-9) + (3x-9)/(3x-9)
    = (6x-12)/(3x-9)
    = (2x-12)/(-9)

    Lim (x2-9)/(x-3) = Lim (x-3)(x+3)/(x-3)1
    x 3 x 3
    Lim = ((x+3))/1
    X 3= (3+3)/1 = 6/1 = 6

    BalasHapus
  10. Anonim6 Mei 2014 pukul 18.31

    a. F(x) = 3x + 1
    G(x) = (x-1)/(x-3)
    (fOg)-1 = f(g(x))
    = f((x-1)/(x-3))
    = 3((x-1)/(x-3))+ 1
    = (3x-3)/(3x-9) + 1
    = (3x-3)/(3x-9) + (3x-9)/(3x-9)
    = (6x-12)/(3x-9)
    = (2x-12)/(-9)

    b. Lim (x2-9)/(x-3) = Lim (x-3)(x+3)/(x-3)1
    x 3 x 3
    Lim = ((x+3))/1
    X 3= (3+3)/1 = 6/1 = 6

    BalasHapus

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